A field team has a real problem to settle: Where did 22.2 dB of factory link margin go? They must decide what happens before they change measured path exponent on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is measured path exponent. The middle card uses this page's rule. The green card is wavelength. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for measured path exponent is 3.5.
- 2
Name the rule. M=Pt-[PL1m+10n log10(d)]-Srx
- 3
Put in the chapter value. Set measured path exponent to 3.5. The page rule gives wavelength as 0.122 m.
- 4
Read the result. Keep m next to the value. Use it only within the limits on this page.
Predict, then change measured path exponent
Try Predict what happens to wavelength. Move one control, calculate, then check your idea.
Observe Every increase in n multiplies the distance-loss slope. Metal, machinery, and geometry are represented by the fitted exponent, while local destructive-interference dead spots can still be worse. Reset to 3.5 and compare wavelength.
Explain Only measured path exponent moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. Establish the one-metre reference
Zigbee channel 20 sits at 2450 MHz, so its wavelength is about 0.122 m. Free-space spreading at one metre contributes 20log10(4π/λ)=40.2 dB before the factory distance term.
2. Name the link-budget moves
Channel to wavelengthf=2405+5(ch−11) MHz; λ=c/f.
Add distance lossPL(d)=PL(1 m)+10n log10(d/1 m).
Subtract from the budgetM=Pt−PL−Srx.
3. Compare clutter with free space
At 30 m, moving from n=2.0 to n=3.5 adds 22.2 dB. That same amount disappears from margin because transmit power and receiver sensitivity are unchanged.
4. Try one controlled change
TryChange only the measured path exponent. Channel 20, 30 m distance, +8 dBm transmitter, and −97 dBm receiver stay fixed.
ObserveAt n=3.5, path loss is 91.9 dB and margin is 13.1 dB. Free space predicts 69.8 dB loss and 35.2 dB margin—a 22.2 dB overstatement.
ExplainEvery increase in n multiplies the distance-loss slope. Metal, machinery, and geometry are represented by the fitted exponent, while local destructive-interference dead spots can still be worse.
The log-distance model compresses a variable factory into one fitted exponent.
- Path exponent
- Must come from site measurements over relevant routes and states
- Link margin
- Does not by itself predict interference, fading tails, retries, or availability
- Radio values
- +8 and −97 dBm are catalog-typical teaching constants
Validate with LQI/RSSI surveys, packet delivery, interference states, and router-loss tests.
5. Reproduce the factory result
Channel 20 gives f=2450 MHz and λ=0.122 m. PL1m=40.2 dB. With n=3.5, 10nlog10(30)=51.7 dB, so PL=91.9 dB and M=8−91.9−(−97)=13.1 dB. With n=2, PL=69.8 dB and margin=35.2 dB.
6. Carry the evidence forward
Record channel and interference occupancy, antenna and enclosure, height and orientation, route geometry, measured n, RSSI/LQI distribution, packet delivery and retries, transmitter setting, sensitivity criterion, router density, and machine states.
7. Check yourself
Why does a larger n reduce margin?
Does 13.1 dB guarantee reliable factory delivery?
Where does 22.2 dB come from?
The page reproduces the chapter’s log-distance comparison without turning one exponent into a site guarantee.
- 13.1 dB
- Modelled margin using fixed n=3.5 and catalog radio values
- 35.2 dB
- Free-space comparison at the same 30 m
- Dead spots
- Local wave interference not resolved by the single-slope model
An industrial approval needs measurements across space, time, and failure states.
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