A field team has a real problem to settle: What does a route repair cost outside the simulator? They must decide what happens before they change repairs per day on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is repairs per day. The middle card uses this page's rule. The green card is steps per repair. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for repairs per day is 24.
- 2
Name the rule. E_step = 0.030 x 3.0 x 0.040 = 3.60 mJ E_repair = (1 + 2 + 5) x 3.60 = 28.8 mJ = 0.008 mWh C_usable = 220 x 0.99^5 x 0.80 = 167.4 mAh
- 3
Put in the chapter value. Set repairs per day to 24. The page rule gives steps per repair as 8.
- 4
Read the result. Keep the stated output unit next to the value. Use it only within the limits on this page.
Predict, then change repairs per day
Try Predict what happens to steps per repair. Move one control, calculate, then check your idea.
Observe Frequency multiplies the fixed physical event cost, so the bounded lifetime falls in direct inverse proportion. Reset to 24 and compare steps per repair.
Explain Only repairs per day moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. Start with the physical story
A graph treats a retransmission as a counter. A battery must supply current at voltage for the whole radio interval, so every counter has an energy cost.
2. Name every algebra move
Count stepsAdd normal, retry, and explorer transmissions.
Price one stepMultiply current, voltage, and time: E = IVt.
Derate the cellApply calendar self-discharge and the reserved margin.
Scale frequencyMultiply repair energy by repair events per day.
Screen lifetimeDivide usable cell energy by daily repair energy.
3. Reproduce the chapter case
E_repair = (1 + 2 + 5) × 3.60 = 28.8 mJ = 0.008 mWh
C_usable = 220 × 0.99^5 × 0.80 = 167.4 mAh
One repair is tiny. At one event each hour, repair traffic alone consumes about 0.192 mWh per day and the bounded repair-only lifetime is about 7.2 years.
4. Try one real input
TryMove the repair frequency. The event cost stays physical while daily drain and the repair-only lifetime recompute together.
ObserveAt 24 repairs per day, repair traffic uses 0.192 mWh per day and the repair-only screen is about 2,615 days.
ExplainFrequency multiplies the fixed physical event cost, so the bounded lifetime falls in direct inverse proportion.
This is a repair-traffic screen, not a battery-life prediction.
- Cell
- Voltage, capacity, self-discharge, resistance, temperature, and cutoff vary by cell and load.
- Radio
- Current and 40 ms step time are explicit model inputs, not a Z-Wave guarantee.
- Workload
- Sleep current, sensing, ordinary reports, inclusion, and battery conversion losses are omitted.
Correct, not complete: this ledger does not predict device lifetime or validate RF behavior.
5. Use the result in validation
Carry repair frequency and step energy into the hardware plan. Measure current pulses and route recovery on the real controller and endpoint.
6. Record the evidence state
Keep firmware, route, retry and explorer counts, radio timing, cell state, temperature, current trace, and the trigger for repeating the test.
7. Check yourself
Why is mAh alone not the event energy?
Why does doubling repair frequency halve this lifetime screen?
Does a seven-year screen prove a seven-year sensor?
The arithmetic prices only the named simulated repair traffic.
- Reproducible
- Step count, IVt energy, derating, and frequency scaling are explicit.
- Measured
- Real current pulses, sag, topology, and retries belong in hardware evidence.
- Excluded
- Sleep, sensing, reporting, leakage, temperature, and conversion losses are outside the ledger.
Correct, not complete: use this as a test trigger, not a battery claim.
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