A field team has a real problem to settle: What does the directional antenna buy? They must decide what happens before they change directional gain on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is directional gain. The middle card uses this page's rule. The green card is omni eirp. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for directional gain is 8.
- 2
Name the rule. EIRPomni=14+2.15=16.15 dBm EIRPdir=14+8=22.0 dBm Δ=5.85 dB; range ratio=10^(5.85/20)=1.96x λ=0.125 m; Ae=0.00785 m²
- 3
Put in the chapter value. Set directional gain to 8. The page rule gives omni eirp as 16.1 dBm.
- 4
Read the result. Keep dBm next to the value. Use it only within the limits on this page.
Predict, then change directional gain
Try Predict what happens to omni eirp. Move one control, calculate, then check your idea.
Observe The /20 exponent appears because received power falls with distance squared. Aperture grows with linear gain and wavelength squared. Reset to 8 and compare omni eirp.
Explain Only directional gain moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. dBi describes direction
A directional antenna redistributes the radio's power. More energy reaches the intended direction, while less reaches other directions.
2. Name every algebra move
Add in decibelsEIRP=Ptx+G.
Subtract the two EIRPsΔEIRP=EIRPdir−EIRPomni.
Undo the range logarithmd2/d1=10^(ΔEIRP/20).
Find wavelengthλ=c/f.
Convert dBi and find apertureGlinear=10^(GdBi/10); Ae=Glinear λ²/(4π).
3. Reproduce the deployment example
EIRPdir=14+8=22.0 dBm
Δ=5.85 dB; range ratio=10^(5.85/20)=1.96×
λ=0.125 m; Ae=0.00785 m²
The range ratio is ideal free-space geometry. The aperture is an equivalent receiving area, not the panel's outline.
4. Try the directional gain
TryChange directional gain while the radio and omni reference stay fixed.
ObserveAt 8 dBi the directional path has 5.85 dB more EIRP than the omni and an ideal 1.96× range ratio.
ExplainThe /20 exponent appears because received power falls with distance squared. Aperture grows with linear gain and wavelength squared.
The widget holds frequency and conducted power fixed.
- Range
- Free-space ratio omits terrain, clutter, Fresnel clearance, interference, and receiver mode
- Pattern
- Real antennas have lobes, nulls, efficiency loss, polarization, and mounting effects
- Rules
- EIRP limits and permitted bands depend on the deployment jurisdiction
Measure the installed pattern and link margin along required paths.
5. Match antenna shape to architecture
Use directionality when the gateway path is fixed and known. A changing or multi-direction topology may value broad coverage more than the ideal range multiplier.
6. Build the deployment record
Record conducted power, antenna model and gain, frequency, orientation, mounting, feedline, EIRP limit, required coverage, measured margin, failure exercise, owner, and retest trigger.
7. Check yourself
Why is directional EIRP 22.0 dBm?
Why is the range ratio not 5.85×?
Does 0.00785 m² equal the physical panel face?
The radio and antenna figures are the chapter's explicit catalog-typical teaching case.
- 1.96×
- Ideal fixed-path range multiplier
- 0.00785 m²
- Effective aperture, not physical size
- 22.0 dBm
- Before feedline and regulatory review
Correct, not complete: site evidence decides whether the antenna belongs.
Packet Pete guides