A field team has a real problem to settle: How does one exponent spend 17 dB of margin? They must decide what happens before they change exponent n on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is exponent n. The middle card uses this page's rule. The green card is wavelength. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for exponent n is 3.
- 2
Name the rule. λ=0.125 m; PL0=40.05 dB; PL=PL0+10nlog10(d/d0) n=3: PL=91.02 dB; extra=16.99 dB; Pr=-91.02 dBm; M=3.98 dB
- 3
Put in the chapter value. Set exponent n to 3. The page rule gives wavelength as 0.125 m.
- 4
Read the result. Keep m next to the value. Use it only within the limits on this page.
Predict, then change exponent n
Try Predict what happens to wavelength. Move one control, calculate, then check your idea.
Observe The exponent multiplies the distance logarithm. A change from n=2 to n=3 adds one whole 10log10(50) term. Reset to 3 and compare wavelength.
Explain Only exponent n moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. Start with the physical question
Compute the 50 m path loss and raw receiver margin from n. A route flag tied to loss rather than a one-time RSSI.
2. Name every algebra move
Find wavelengthλ=c/f.
Build the 1 m referencePL0=20log10(4πd0/λ).
Scale with distanceAdd 10nlog10(d/d0).
Find received powerPr=Pt+Gt+Gr−PL.
Compare with sensitivityM=Pr−Prx,min.
3. Reproduce the chapter case
n=3: PL=91.02 dB; extra=16.99 dB; Pr=−91.02 dBm; M=3.98 dB
The arithmetic reproduces the chapter case while keeping its assumptions explicit.
4. Try the controlling input
TryMove the control and watch every displayed result come from the shown formula.
ObserveAt n=3.00, the 50 m loss is 91.02 dB, 16.99 dB above free space, leaving 3.98 dB raw margin.
ExplainThe exponent multiplies the distance logarithm. A change from n=2 to n=3 adds one whole 10log10(50) term.
This compact engine isolates one relationship; it is not a deployment certificate.
- Reference
- The 1 m value is ideal free space
- Environment
- One exponent and zero shadowing cannot describe every location
- Margin
- Raw margin omits the deployment’s required reserve and interference
Measure the real system and reopen the decision when its inputs change.
5. Turn the number into a route test
Measure delivery, retries, asymmetry, parent changes, and margin over time. Shorten or repair a link when the required reserve is not held.
6. Keep the link record
Record frequency, reference distance, exponent evidence, distance, antenna state, transmit power, sensitivity, shadowing spread, reserve, measurements, owner, and retest trigger.
7. Check yourself
Why is the wavelength about 0.125 m?
Where does the extra 16.99 dB come from?
Is 3.98 dB an accepted link margin?
The worked values are traceable chapter examples or explicitly labelled teaching assumptions.
- 2.4 GHz and 50 m
- Explicit chapter example
- n=3
- Catalog-typical obstructed teaching value
- 3.98 dB
- Raw ideal margin before deployment reserve
Correct, not complete: field evidence still decides acceptance.
Packet Pete guides