A field team has a real problem to settle: Why does the relay die before identical edge nodes? They must decide what happens before they change downstream nodes on the device. Predict the direction first.
See the relationship first
Set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for downstream nodes is 5.
- 2
Name the rule. Qusable=0.80x2000=1600 mAh tedge=1600/0.050=32,000 h=3.65 years Irelay=0.050(1+5)=0.300 mA=300 uA trelay=1600/0.300=5,333 h≈7.3 months 20log10(2400/868)=8.83 dB; ideal range=2.76x
- 3
Put in the chapter value. Set downstream nodes to 5. The page ledger gives relay years as 0.6 years.
- 4
Read the result. Keep years beside the value. Use it only within the limits on this page.
Predict, then change downstream nodes
Try Predict what happens to relay years. Move one control, calculate, then check your idea.
Observe Predict a decrease in relay years as the input increases over this range. Reset to the chapter baseline and compare.
Explain Only downstream nodes moves here. The other chapter values stay fixed.
Source: content/wsn/wsn-deployment-sizing.qmd — Phoebe's Field Notes: Why The Relay Hotspot Dies First On The Same Battery. Use the chapter equation and fixed ledger above; only the named input varies.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. Identical hardware can carry unequal work
An edge node sends its own readings. A relay sends its own plus the traffic forwarded for downstream nodes, so identical cells can reach the same usable charge floor at very different times.
2. Name every algebra move
Derate nameplate capacityQusable=fQnominal.
Count the relay's traffic sharesIrelay≈Iedge(1+n).
Divide one capacity twicetedge=Qusable/Iedge; trelay=Qusable/Irelay.
Compare bands in dBΔFSPL=20log10(fhigh/flow).
Undo the distance logarithmrange ratio=10^(ΔFSPL/20).
3. Reproduce the hotspot case
tedge=1600/0.050=32,000 h=3.65 years
Irelay=0.050(1+5)=0.300 mA=300 µA
trelay=1600/0.300=5,333 h≈7.3 months
20log10(2400/868)=8.83 dB; ideal range=2.76×
The lower-band range is a possible topology lever, not a promise that relay count will fall.
4. Try downstream load
TryChange how many downstream nodes the relay carries.
ObserveAt five downstream nodes, relay current is 300 µA and life falls to 5,333 h or about 7.3 months while edge life remains 3.65 years.
ExplainEach downstream share adds another edge-current unit in this model. Capacity stays fixed, so relay life shrinks in inverse proportion.
The relay-current relation is a role-loading approximation.
- Traffic
- Payloads, aggregation, receive cost, retransmissions, routes, and reporting schedules vary
- Battery
- Pulse sag, self-discharge, temperature, cutoff, and rate effects are omitted
- Range
- The band comparison is free-space only and does not determine topology by itself
Measure per-role state currents and validate the actual relay tree.
5. Size for the hotspot, not the average
Mitigations include rotating relay roles, adding gateways, changing routes, aggregating traffic, reducing reporting load, using larger energy stores, or shortening service intervals.
6. Build the sizing record
Record role, downstream count, traffic schedule, state currents, route and retry evidence, capacity and cutoff, band and measured reach, maintenance target, mitigation, owner, and retest trigger.
7. Check yourself
Why is relay current 300 µA?
Why does the same cell last only about 7.3 months?
Does 868 MHz guarantee fewer relays?
The battery, current, downstream-count, and band figures are the chapter's explicit representative case.
- 300 µA
- Linear traffic-share approximation
- 7.3 months
- Bounded relay ledger
- 2.76×
- Ideal band range comparison
Correct, not complete: commissioning evidence must validate role load and coverage.
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