A field team has a real problem to settle: Why can a full drone pack still fail a climb? They must decide what happens before they change climb current on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is climb current. The middle card uses this page's rule. The green card is nameplate energy. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for climb current is 45.
- 2
Name the rule. E=22.2x10.0=222 Wh; Eusable=0.80x222=177.6 Wh Cruise: ΔV=25x0.040=1.00 V; climb: ΔV=45x0.040=1.80 V; Vterm=20.4 V
- 3
Put in the chapter value. Set climb current to 45. The page rule gives nameplate energy as 222.00 Wh.
- 4
Read the result. Keep Wh next to the value. Use it only within the limits on this page.
Predict, then change climb current
Try Predict what happens to nameplate energy. Move one control, calculate, then check your idea.
Observe Watt-hours bound mission duration; IxR sets the instant voltage drop. The launch and segment gates need both checks. Reset to 45 and compare nameplate energy.
Explain Only climb current moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. Start with two battery questions
Energy asks how much work the pack can supply over a mission. Loaded voltage asks whether it can supply the current demanded right now. Passing one does not pass the other.
2. Name every algebra move
Convert charge to energyEnameplate=V×Q.
Protect reserveEusable=k×Enameplate.
Calculate sagΔV=I×Rint.
Subtract the dropVterm=Voc−ΔV.
Age stored chargeQ(t)=Q0(1−r)^t.
3. Reproduce the chapter case
Cruise: ΔV=25×0.040=1.00 V; climb: ΔV=45×0.040=1.80 V; Vterm=20.4 V
After half a month at 2% monthly self-discharge, the model retains 9,899 mAh and loses about 101 mAh.
4. Try the climb current
TryRaise the worst-segment current and watch voltage headroom shrink while stored energy stays unchanged.
ObserveAt 45.00 A, climb sag is 1.80 V or 8.11%, leaving 20.40 V. The 222.00 Wh nameplate and 177.60 Wh planned budget do not move with current.
ExplainWatt-hours bound mission duration; I×R sets the instant voltage drop. The launch and segment gates need both checks.
This compact engine is a first-order pack model, not a flight certificate.
- Voltage
- 22.2 V is treated as a fixed open-circuit teaching value rather than a discharge curve
- Resistance
- 40 mΩ is held constant despite temperature, age, state of charge, and connector heating
- Mission
- Energy excludes wind, manoeuvres, payload variation, conversion loss, and return uncertainty
Use measured pack and flight logs, with an explicit cutoff and reserve policy.
5. Build the segment gate
For every transit, climb, dwell, collection, and return segment, estimate energy and maximum current. Reject or trim the plan if either reserve energy or loaded-voltage margin fails.
6. Keep the pack record
Record pack chemistry, voltage, measured capacity, resistance, temperature, age, storage interval, segment currents, cutoff, reserve, route, payload, wind, owner, and abort trigger.
7. Check yourself
Why is 10 Ah not yet an energy budget?
Why does climb sag exceed cruise sag?
Does 177.6 Wh prove the mission is safe?
The pack values are the chapter's explicitly labelled catalog-typical teaching case.
- 22.2 V and 10.0 Ah
- Catalog-typical 6S mapping-drone pack
- 25/45 A and 40 mΩ
- Catalog-typical cruise, climb, and pack resistance assumptions
- 2% and 20%
- Illustrative monthly self-discharge and design reserve
Correct, not complete: qualify the actual pack and aircraft before flight.
Motion Marley guides