A field team faces an unresolved physical question: Where did the missing LED current go? They must answer it before changing led drop on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is led drop. The middle card applies this page's relationship. The green card is resistor voltage. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for led drop is 2.
- 2
Name the relationship. VR=5.0-2.0=3.0 V Rcorrect=3.0/0.020=150 ohm Rwrong=5.0/0.020=250 ohm Iactual=3.0/250=12.0 mA shortfall=40.0%
- 3
Substitute the chapter fixture. Set led drop to 2. The page ledger gives resistor voltage as 3.00 V.
- 4
Read the result. Keep V beside the value. Use it only inside the technical boundary on this page.
Predict, then change led drop
Try Predict the direction of resistor voltage. Move one control, calculate, then check your prediction.
Observe Kirchhoff accounting couples the component drop to current; ignoring one series drop cannot be repaired by later rounding. Reset the control to 2 and compare resistor voltage.
Explain Only led drop moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Start with the physical story
Every volt around a series loop must be spent once. The LED claims its forward drop first; the resistor receives only the remainder.
2. Name every algebra move
Write the loopVsupply=IR+Vf.
Isolate the resistor voltageVR=Vsupply−Vf.
Size the resistorR=VR/Itarget.
Replay the mistakeRwrong=Vsupply/Itarget.
Find real currentIactual=VR/Rwrong.
3. Reproduce the chapter case
Rcorrect=3.0/0.020=150 Ω
Rwrong=5.0/0.020=250 Ω
Iactual=3.0/250=12.0 mA
shortfall=40.0%
The wrong design is dim rather than dramatic, which is why this bookkeeping error survives reviews.
4. Try one real input
TryMove the control, predict the direction, then compare every output.
ObserveA larger LED drop leaves less voltage for the resistor, so the correct resistance and actual current both fall while the shortcut stays frozen at 250 Ω.
ExplainKirchhoff accounting couples the component drop to current; ignoring one series drop cannot be repaired by later rounding.
This is a transparent first-order teaching ledger tied to the chapter constants.
- LED model
- Forward voltage is treated as fixed at the chosen operating point.
- Tolerance
- Real Vf, resistor value, supply voltage, and temperature all vary.
- Drive
- GPIO current and package power limits still need separate checks.
Correct, not complete: this ledger does not qualify an LED, resistor, GPIO, or thermal design.
5. Use the result in the design
Choose a worst-case Vf range, calculate current at both ends, select a standard resistor, then verify pin current and resistor power.
6. Record the evidence state
Record supply tolerance, LED Vf bin and test current, resistor tolerance, measured loop current, temperature, and GPIO limits.
7. Check yourself
Why subtract Vf?
Why can the bad design look harmless?
Is a fixed Vf exact?
The arithmetic reproduces the named chapter case; it is an inspectable model, not a component approval.
- LED model
- Forward voltage is treated as fixed at the chosen operating point.
- Tolerance
- Real Vf, resistor value, supply voltage, and temperature all vary.
- Drive
- GPIO current and package power limits still need separate checks.
Correct, not complete: this ledger does not qualify an LED, resistor, GPIO, or thermal design.
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