A field team faces an unresolved physical question: How does a ten-second radio burst become a battery-life result? They must answer it before changing transmit time on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is transmit time. The middle card applies this page's relationship. The green card is active charge. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for transmit time is 10.
- 2
Name the relationship. 25(30)/3600 = 0.208 mAh; 120(10)/3600 = 0.333 mAh 0.01(3,560)/3600 = 0.00989 mAh; Iavg = 0.552 mA 2,500/0.552 = 4,530 h = 189 days
- 3
Substitute the chapter fixture. Set transmit time to 10. The page ledger gives active charge as 0.208.
- 4
Read the result. Keep the stated output unit beside the value. Use it only inside the technical boundary on this page.
Predict, then change transmit time
Try Predict the direction of active charge. Move one control, calculate, then check your prediction.
Observe Usable lifetime is a measured charge ledger, not the printed cell capacity divided by a guessed current. Reset the control to 10 and compare active charge.
Explain Only transmit time moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Count charge, not labels
Current is charge flow. Multiply each state's current by its time, sum the hourly charge, and divide usable capacity by that average current.
2. Name every algebra move
Convert seconds to hoursQi=Iiti/3600.
Add statesIavg=ΣQi for a one-hour ledger.
Derate capacityCusable=C(1−d).
Dividetlife=Cusable/Iavg.
Subtract sagVload=Voc−IR.
3. Reproduce the chapter
0.01(3,560)/3600 = 0.00989 mAh; Iavg = 0.552 mA
2,500/0.552 = 4,530 h = 189 days
The chapter's 4,545-hour result uses its rounded 0.55 mA display; the unrounded ledger gives 4,530 hours.
4. Try the radio time
TryShorten the burst while keeping the 30-second sensing state.
ObserveThe radio dominates this baseline ledger; shortening it moves lifetime directly.
ExplainUsable lifetime is a measured charge ledger, not the printed cell capacity divided by a guessed current.
States are constant-current rectangles.
- Cell
- No nonlinear discharge curve, ageing, or temperature response
- Radio
- No startup, retry, or network-search variation
- Voltage
- One resistance term, not a transient cell model
Profile the complete device across temperature and network conditions.
5. Add real losses
Repeat the ledger with cold derating, self-discharge, converter efficiency, retries, and the measured cutoff voltage.
6. Keep evidence
Version firmware state timings, current traces, cell lot, temperature, network condition, and calculation sheet.
7. Check yourself
Why divide seconds by 3,600?
Why do 4,530 and 4,545 hours differ?
Does nominal mAh guarantee field life?
The baseline timings and currents come from the chapter; sag terms are stated checks.
- 30 s, 10 s, 3,560 s
- Chapter states
- 2,500 mAh
- Chapter baseline cell
- 2 Ω
- Interactive teaching assumption
Correct, not complete: a compact ledger does not qualify a battery-powered product.
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