Actuator Classification Calculation Audit
Actuator Classification Calculation Audit
Ada re-derives this chapter’s own numbers step by step, at full precision
ADA · CALCULATION AUDIT
Actuator Classification Calculation Audit
A door controller can drive a relay strike, a solenoid bolt, or a motorized latch, and the same “open” command hides very different loads: the strike pulls 1.5 A at 12 V for 18 W, its 80 mA coil still needs a driver and flyback path, and a 0.5 A solenoid dissipates 6 W held but only about 1 W when pulsed 10 s every 60 s. A companion vent load of 1.2 N at a 35 mm arm sets a 0.105 N m target once a 2.5x margin is applied. This audit re-derives each figure and asks whether one software verb can quietly cross a torque, startup-current, switched-power, or thermal boundary, so the selection record must name the matching physical proof.
Companion to the chapter Choosing the Right Actuator — every number here comes from that chapter.
The mathematics checks whether the chapter's examples point to the same classification boundary. The physics reminder is that torque, startup current, contact power, and coil heat are different failure surfaces even when the software command looks identical.
See the relationship before changing it
The figure reads from left to right. The blue card is strike current. The middle card applies this page's rule. The green card is strike electrical power. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This model keeps those stated values fixed and changes only strike current, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline is 1.5 A.
- 2
Name the relationship. power = 12 V x strike current
- 3
Substitute with units. 12 V x 1.5 A = 18.0 W
- 4
Read the result. Keep the unit beside the value. Use it only inside the technical boundary on this page.
Predict, then change strike current
Try Predict the direction of power = 12 V x strike current. Test another strike current, then compare strike electrical power.
Observe Current turns the same twelve-volt command into a larger driver and thermal load. Reset strike current to 1.5 and compare strike electrical power.
Explain Current turns the same twelve-volt command into a larger driver and thermal load.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
The chapter's values
Use only the chapter values above: a 1.2 N vent load at a 35 mm arm, a 2.5x margin, a 12 V fan at 0.7 A running and 2.1 A startup, a 1.5 A door strike at 12 V, an 80 mA relay coil, and a 0.5 A solenoid pulsed for 10 s every 60 s.
The worked checks
| Check | Arithmetic | Classification Evidence |
|---|---|---|
| Vent torque | 1.2 N x 0.035 m = 0.042 N m |
The vent is a positioned-motion problem, so torque and final-state evidence matter. |
| Margin target | 0.042 N m x 2.5 = 0.105 N m |
The actuator family must clear the load with margin, not merely rotate in free air. |
| Fan running power | 12 V x 0.7 A = 8.4 W |
A continuous-flow actuator needs a real power driver and process evidence. |
| Fan startup ratio | 2.1 A / 0.7 A = 3.0 |
The startup case is three times the running current, so normal current alone is not a safe sizing record. |
| Door strike load | 12 V x 1.5 A = 18 W |
The relay or driver switches a DC load; command acknowledgement does not prove the door moved or secured. |
| Relay coil boundary | 12 V x 0.080 A = 0.96 W |
The coil is smaller than the strike load, but it still needs a transistor driver and flyback path. |
| Solenoid duty heat | 12 V x 0.5 A = 6 W; 10 / 60 = 0.1667; 6 W x 0.1667 = 1.0 W |
The pulsed heat case is about one watt before enclosure effects; continuous hold is six watts. |
Audit conclusion: actuator classification is quantitative evidence. The same software verb can cross a torque boundary, a startup-current boundary, a switched-power boundary, or a thermal boundary, so the selection record must name the physical proof that matches the family.
Every number above is taken from the chapter’s own examples and re-derived step by step.
Audit result
The 12 V, 0.5 A solenoid is 6 W held and about 1 W at 10/60 duty; that does not prove the bolt moved.