A field team has a real problem to settle: Should the gateway spend 7 dB on range or battery? They must decide what happens before they change directional gain on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is directional gain. The middle card uses this page's rule. The green card is gain available. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for directional gain is 9.15.
- 2
Name the rule. ΔG=9.15-2.15=7.00 dB; range=2.24x 10.0-7.00=3.00 dBm: 10.0 mW becomes 2.00 mW IPA=8.66 mA becomes 1.73 mA 1% TX ledger: 455 days becomes 5.13 years, a 4.11x extension
- 3
Put in the chapter value. Set directional gain to 9.15. The page rule gives gain available as 7.00 dB.
- 4
Read the result. Keep dB next to the value. Use it only within the limits on this page.
Predict, then change directional gain
Try Predict what happens to gain available. Move one control, calculate, then check your idea.
Observe Range uses the square-root dB relation. The battery path first converts dBm to power, then power to PA current, then duty-weights current. Reset to 9.15 and compare gain available.
Explain Only directional gain moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. One gain can fund two budgets
A directional gateway can keep leaf transmit power fixed and increase ideal range, or keep the link budget fixed and let the leaf reduce transmit power.
2. Name every algebra move
Subtract antenna gainsΔG=Gdir−Gomni.
Spend on rangerange ratio=10^(ΔG/20).
Or spend on powerPnew,dBm=Pold,dBm−ΔG.
Convert dBm to milliwatts and currentPmW=10^(PdBm/10); I=P/(ηV).
Weight transmit and sleep, then divideIavg=DITX+(1−D)Isleep; t=C/Iavg.
3. Reproduce the chapter trade
10.0−7.00=3.00 dBm: 10.0 mW becomes 2.00 mW
IPA=8.66 mA becomes 1.73 mA
1% TX ledger: 455 days becomes 5.13 years, a 4.11× extension
The battery comparison holds coverage and link margin fixed by spending the gain on lower transmit power.
4. Try the gateway gain
TryMove directional gain and watch both possible purchases change.
ObserveAt 9.15 dBi, 7.00 dB can buy 2.24× ideal range or reduce the leaf setting to 3.00 dBm and extend the bounded ledger by 4.11×.
ExplainRange uses the square-root dB relation. The battery path first converts dBm to power, then power to PA current, then duty-weights current.
This trade holds link budget, efficiency, duty cycle, sleep current, and capacity fixed.
- Radio
- Real PA current is not a single constant-efficiency curve
- Traffic
- Receive, processing, startup, retries, and acknowledgements are omitted
- Antenna
- Pattern, orientation, polarization, feedline, and field loss can spend the gain
Measure current states and link margin at the chosen transmit setting.
5. State which benefit you took
A design can divide gain between more range, lower transmit power, and more fade reserve. Record that allocation rather than quoting every maximum simultaneously.
6. Build the trade record
Record antenna patterns and mounting, leaf TX setting, PA current curve, duty states, sleep current, capacity and cutoff, measured margin, required coverage, allocation decision, owner, and retest trigger.
7. Check yourself
Why does 7.00 dB give 2.24× ideal range?
Why can TX fall from 10 to 3 dBm?
Does 5.13 years predict a real leaf node?
All antenna, radio, efficiency, duty, sleep, and capacity values are the chapter's explicit catalog-typical example.
- 2.24×
- Ideal range alternative
- 5.13 years
- Bounded lower-power ledger
- 4.11×
- Comparison within the same simplified model
Correct, not complete: field measurements decide how the gain can be spent.
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