A field team has a real problem to settle: What physical chain sits behind an accelerometer sensitivity row? They must decide what happens before they change acceleration on the device. Predict the direction first.
See the relationship first
The figure reads from left to right. The blue card is acceleration. The middle card uses this page's rule. The green card is acceleration. Follow the arrows: set the input, use the rule, then read the result and its unit.
The audit later on checks more than one number. Here, the added model uses the baseline named below and holds every other chapter value fixed. That sentence bridges the fixtures, so the numbers do not change without a reason.
Derive the baseline in four moves
- 1
Name the input. The chapter baseline for acceleration is 2.
- 2
Name the rule. a=2x9.81=19.6 m/s² x=(3.0x10⁻⁸x19.6)/8=73.6 nm x/d₀=3.68%; ΔC=0.0736 pF Vout=1.0x0.0736/1.0=73.6 mV Sensitivity=73.6/2=36.8 mV/g
- 3
Put in the chapter value. Set acceleration to 2. The page rule gives acceleration as 19.62 m/s^2.
- 4
Read the result. Keep m/s^2 next to the value. Use it only within the limits on this page.
Predict, then change acceleration
Try Predict what happens to acceleration. Move one control, calculate, then check your idea.
Observe The fixed sensitivity comes from fixed mechanical and electrical constants; manufacturing and environment make those constants uncertain. Reset to 2 and compare acceleration.
Explain Only acceleration moves here. The other chapter values stay fixed.
Check yourself
What should you do before you trust the result?
What does this small model leave out?
1. Begin with a mass on a spring
Acceleration creates force on a proof mass. The spring moves until its restoring force balances that inertial force. The movement is tiny but measurable as a capacitance change.
2. Name every algebra move
Convert ga=ag×9.81 m/s².
Balance forcex=ma/k.
Compare with the gapΔC/C₀≈x/d₀.
Find capacitance changeΔC=C₀x/d₀.
Read charge as voltageVout=VrefΔC/Cf.
3. Reproduce the 2 g case
x=(3.0×10⁻⁸×19.6)/8=73.6 nm
x/d₀=3.68%; ΔC=0.0736 pF
Vout=1.0×0.0736/1.0=73.6 mV
Sensitivity=73.6/2=36.8 mV/g
The result is an internal analog teaching estimate, not the LIS3DH or ADXL345 digital LSB/g specification.
4. Try the acceleration
TryMove the input while the small-deflection approximation and die constants stay fixed.
ObserveIn this linear model, deflection, capacitance change, and output all scale with acceleration while mV/g stays fixed.
ExplainThe fixed sensitivity comes from fixed mechanical and electrical constants; manufacturing and environment make those constants uncertain.
This is a small-deflection static chain, not a MEMS device model.
- Mechanics
- Damping, resonance, cross-axis motion, and stops are omitted
- Capacitance
- Comb geometry and differential readout are reduced to one gap approximation
- Electronics
- Noise, nonlinearity, ADC scaling, temperature, and digital calibration are omitted
Use the manufacturer's tested sensitivity, tolerance, temperature, supply, bandwidth, and noise conditions for selection.
5. Ask which tolerance dominates
Trace mass, spring, gap, rest capacitance, feedback capacitance, and reference voltage into the sensitivity error budget before accepting one summary number.
6. Preserve the evidence row
Record device, range, sensitivity condition, temperature, supply, bandwidth, axis, tolerance type, calibration state, and the bench check that can reject the choice.
7. Check yourself
Why must 2 g become 19.6 m/s²?
Why is 73.6 nm allowed in the linear approximation?
Is 36.8 mV/g the ADXL345's published digital sensitivity?
The page reproduces the chapter's catalog-typical MEMS-comb constants.
- 73.6 nm
- Static deflection under stated ideal constants
- 0.0736 pF
- Approximate capacitance change
- 36.8 mV/g
- Internal analog estimate, not a digital datasheet guarantee
Correct, not complete: this chain does not qualify an accelerometer selection.
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