A field team faces an unresolved physical question: Why is a 4000 mAh phone not a 4000 mAh gateway? They must answer it before changing peak current on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is peak current. The middle card applies this page's relationship. The green card is nameplate energy. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for peak current is 1.5.
- 2
Name the relationship. E=15.40 Wh; Cusable=3200 mAh; Eusable=12.32 Wh; Isustainable=400 mA Vsag=IRint; at 1.5 A: 0.225 V and Vterminal=3.625 V
- 3
Substitute the chapter fixture. Set peak current to 1.5. The page ledger gives nameplate energy as 15.40 Wh.
- 4
Read the result. Keep Wh beside the value. Use it only inside the technical boundary on this page.
Predict, then change peak current
Try Predict the direction of nameplate energy. Move one control, calculate, then check your prediction.
Observe The reserve limits average gateway work, while internal resistance creates a separate instantaneous voltage limit during radio and screen bursts. Reset the control to 1.5 and compare nameplate energy.
Explain Only peak current moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Start with the physical question
Turn a phone label into a bounded gateway power budget. A runtime and brownout guardrail that names its assumptions.
2. Name every algebra move
Convert mAh to AhDivide by 1000 before multiplying by volts.
Hold the reserveMultiply charge and energy by 0.80.
Spread charge across the shiftIsustainable=Cusable/t.
Apply Ohm’s law to the burstVsag=IRint.
Subtract the sagVterminal=Voc−Vsag.
3. Reproduce the chapter case
Vsag=IRint; at 1.5 A: 0.225 V and Vterminal=3.625 V
The arithmetic reproduces the chapter case while keeping its assumptions explicit.
4. Try the controlling input
TryMove the control and watch every displayed result come from the shown formula.
ObserveAt 1.50 A, nameplate energy is 15.40 Wh, usable capacity is 3200 mAh, shift current is 400.000 mA, and terminal voltage is 3.625 V.
ExplainThe reserve limits average gateway work, while internal resistance creates a separate instantaneous voltage limit during radio and screen bursts.
This compact engine isolates one relationship; it is not a deployment certificate.
- Phone load
- The 400 mA budget excludes calls, display, navigation, and other apps
- Battery
- Temperature, ageing, cutoff curve, and power-conversion loss are omitted
- Burst
- One resistance value cannot qualify every state of charge
Measure the real system and reopen the decision when its inputs change.
5. Budget average and burst separately
Measure the gateway duty-cycle average with ordinary user load, then capture worst radio, GPS, encryption, and display bursts against the real shutdown threshold.
6. Keep the mobile power record
Record phone model, battery health, usable reserve, shift target, user workload, radio policy, average and peak current, voltage floor, temperature, result, owner, and retest trigger.
7. Check yourself
Why is nameplate energy 15.40 Wh?
Why is the eight-hour current 400 mA?
Does a 3.625 V result prove the phone will stay on?
The worked values are traceable chapter examples or explicitly labelled teaching assumptions.
- 4000 mAh and 3.85 V
- Representative modern phone pack
- 20%
- Explicit operating reserve
- 0.150 Ω
- Catalog-typical teaching resistance
Correct, not complete: field evidence still decides acceptance.
Gateway Gus guides