A field team faces an unresolved physical question: How does a battery-free lens bridge time away from its reader? They must answer it before changing reader gap on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is reader gap. The middle card applies this page's relationship. The green card is wavelength. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for reader gap is 30.
- 2
Name the relationship. λ=3.00x10^8/13.56x10^6=22.1 m dnf=λ/(2π)=3.52 m; 5 cm is 1.42% of dnf Esense=6x2 uWx0.150 s=1.80 uJ Esleep=0.2 uWx1800 s=360 uJ C=2x361.8 uJ/(1.5 V)²=322 uF I≤2 uW/0.6 V=3.33 uA
- 3
Substitute the chapter fixture. Set reader gap to 30. The page ledger gives wavelength as 22.12 m.
- 4
Read the result. Keep m beside the value. Use it only inside the technical boundary on this page.
Predict, then change reader gap
Try Predict the direction of wavelength. Move one control, calculate, then check your prediction.
Observe At constant load, stored energy grows with time; at constant voltage, capacitance must grow with that energy. Reset the control to 30 and compare wavelength.
Explain Only reader gap moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Start with the physical story
The reader and lens behave more like loosely coupled coils than distant antennas. When the reader is absent, a capacitor must supply sensing and sleep energy. Its voltage stores energy quadratically.
2. Name every algebra move
Find wavelengthDivide light speed by 13.56 MHz.
Mark near fieldDivide wavelength by 2π and compare with 5 cm.
Count readingsDivide the reader gap by the five-minute reading interval.
Add energyUse power times time for sensing and sleep.
Solve for capacitanceRearrange E=CV²/2 into C=2E/V².
Bound electrode currentDivide 2 microwatts by 0.6 V.
3. Reproduce the chapter case
dnf=λ/(2π)=3.52 m; 5 cm is 1.42% of dnf
Esense=6×2 µW×0.150 s=1.80 µJ
Esleep=0.2 µW×1800 s=360 µJ
C=2×361.8 µJ/(1.5 V)²=322 µF
I≤2 µW/0.6 V=3.33 µA
The storage result is large for a lens-scale device, so the gap, sleep load, voltage window, and leakage all matter.
4. Try one real input
TryChange the time away from the reader and predict how storage capacitance scales.
ObserveDoubling the gap nearly doubles required capacitance because sleep energy dominates and voltage stays fixed.
ExplainAt constant load, stored energy grows with time; at constant voltage, capacitance must grow with that energy.
This is an ideal energy-balance screen.
- Coupling
- The near-field boundary classifies regime; it does not calculate mutual inductance or delivered power.
- Capacitor
- Leakage, rectifier loss, ESR, allowed voltage drop, and geometry are omitted.
- Biosensor
- Power divided by bias is only an upper current bound, not analyte calibration.
Correct, not complete: a sufficient ideal capacitor does not prove a safe or clinically useful lens.
5. Use the result in the design
Measure harvested power versus alignment and separation, then integrate the real load and choose an allowed capacitor voltage window.
6. Record the evidence state
Keep coil geometry, distance, alignment, frequency, rectifier efficiency, storage capacitance, leakage, voltage limits, sensing cadence, electrode bias, temperature, and exposure limits.
7. Check yourself
Why is a 5 cm lens-reader path not a far-field link?
Why does a longer reader gap need more capacitance?
Does 3.33 microamps predict glucose concentration?
The arithmetic extends the chapter's illustrative frequency, gap, power, and voltage values.
- Coupling
- The near-field boundary classifies regime; it does not calculate mutual inductance or delivered power.
- Capacitor
- Leakage, rectifier loss, ESR, allowed voltage drop, and geometry are omitted.
- Biosensor
- Power divided by bias is only an upper current bound, not analyte calibration.
Correct, not complete: a sufficient ideal capacitor does not prove a safe or clinically useful lens.
Light Lucy guides