A field team faces an unresolved physical question: Why does a silicon diode look as if it has a knee? They must answer it before changing temperature on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is temperature. The middle card applies this page's relationship. The green card is temperature. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for temperature is 300.
- 2
Name the relationship. VT=(1.380649e-23x300)/(1.602176634e-19)=25.852 mV decade step=VT ln(10)=59.526 mV 120 mV/59.526 mV=2.016 decades current ratio=exp(120/25.852)=103.73x
- 3
Substitute the chapter fixture. Set temperature to 300. The page ledger gives temperature as 26.85 degrees C.
- 4
Read the result. Keep degrees C beside the value. Use it only inside the technical boundary on this page.
Predict, then change temperature
Try Predict the direction of temperature. Move one control, calculate, then check your prediction.
Observe Temperature appears inside the exponential scale; it changes the slope before package resistance and self-heating are considered. Reset the control to 300 and compare temperature.
Explain Only temperature moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Start with the physical story
A junction is not an ideal switch. Thermal motion gives carriers a voltage scale, and each extra slice of forward voltage multiplies how many cross the barrier.
2. Name every algebra move
Build thermal voltageUse VT=kT/q.
Convert to millivoltsMultiply volts by 1000.
Find one current decadeMultiply VT by ln(10).
Price a voltage changeDivide the chosen rise by the decade step.
Recover the ratioUse exp(deltaV/VT).
3. Reproduce the chapter case
decade step=VT ln(10)=59.526 mV
120 mV/59.526 mV=2.016 decades
current ratio=exp(120/25.852)=103.73×
Two 60 mV-like steps explain why a small voltage rise can look like an abrupt knee.
4. Try one real input
TryMove the control, predict the direction, then compare every output.
ObserveRaising temperature raises VT and the millivolts per decade, so the same 120 mV increase buys fewer current decades.
ExplainTemperature appears inside the exponential scale; it changes the slope before package resistance and self-heating are considered.
This is a transparent first-order teaching ledger tied to the chapter constants.
- Model
- This is the ideal Shockley exponential with ideality factor one.
- Current
- Series resistance and high injection reshape the curve at larger current.
- Temperature
- Real junction temperature follows self-heating and ambient conditions.
Correct, not complete: this ledger does not select, derate, or thermally qualify a diode.
5. Use the result in the design
Use the decade slope to sanity-check a measured I-V curve, then add ideality factor, series resistance, leakage, and temperature limits from the datasheet.
6. Record the evidence state
Record junction temperature, forward current, forward voltage, ideality assumptions, pulse duration, package temperature, and instrument uncertainty.
7. Check yourself
Why does 0.7 V look like a threshold?
Does every silicon diode drop exactly 0.7 V?
What changes when temperature rises?
The arithmetic reproduces the named chapter case; it is an inspectable model, not a component approval.
- Model
- This is the ideal Shockley exponential with ideality factor one.
- Current
- Series resistance and high injection reshape the curve at larger current.
- Temperature
- Real junction temperature follows self-heating and ambient conditions.
Correct, not complete: this ledger does not select, derate, or thermally qualify a diode.
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