A field team faces an unresolved physical question: How does heater duty cycle become battery runtime? They must answer it before changing heater on-time on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is heater on-time. The middle card applies this page's relationship. The green card is heater duty. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for heater on-time is 30.
- 2
Name the relationship. duty=30/300=10.0% Iheater,avg=150 mAx0.10=15.0 mA Pbase=(3.3 V)(92.4 mA)=305 mW Pheater=(5 V)(15.0 mA)=75.0 mW t=7.40 Wh/0.380 W=19.5 h
- 3
Substitute the chapter fixture. Set heater on-time to 30. The page ledger gives heater duty as 10.0%.
- 4
Read the result. Keep % beside the value. Use it only inside the technical boundary on this page.
Predict, then change heater on-time
Try Predict the direction of heater duty. Move one control, calculate, then check your prediction.
Observe Duty fraction scales the heater row before power rows are added. Battery energy is fixed, so more average watts consume it faster. Reset the control to 30 and compare heater duty.
Explain Only heater on-time moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Start with the physical story
A milliamp on 5 V consumes more power than a milliamp on 3.3 V. Add each rail as voltage times time-weighted current, then compare total average power with battery energy. Duty-cycling the heater changes only its time share.
2. Name every algebra move
Find duty fractionDivide heater-on seconds by the 300 s cycle.
Average heater currentMultiply 150 mA by that fraction.
Convert each rail to powerUse P=VI for the 3.3 V base and 5 V heater.
Find stored energy2.000 Ah×3.7 V=7.40 Wh.
Estimate runtimeDivide watt-hours by average watts.
3. Reproduce the chapter case
Iheater,avg=150 mA×0.10=15.0 mA
Pbase=(3.3 V)(92.4 mA)=305 mW
Pheater=(5 V)(15.0 mA)=75.0 mW
t=7.40 Wh/0.380 W=19.5 h
Keeping the non-heater loads continuously active makes the ideal duty-cycled result close to the chapter's 19.5-hour estimate.
4. Try one real input
TryMove heater-on time and predict total power and ideal runtime.
ObserveHeater current and power rise linearly with on-time; total power rises and ideal runtime falls nonlinearly because the fixed base load remains.
ExplainDuty fraction scales the heater row before power rows are added. Battery energy is fixed, so more average watts consume it faster.
This is an ideal energy budget with fixed rail currents and lossless voltage conversion.
- Battery
- Usable energy changes with load, temperature, ageing, cutoff voltage, and cell chemistry.
- Converters
- Regulator efficiency and quiescent current must be included per rail.
- Loads
- Boot, radio retries, sensor warm-up, heater regulation, and sleep states vary.
Correct, not complete: this ledger does not predict field battery life or qualify the heater cycle.
5. Use the result in the design
Measure every rail in each state, multiply by real state durations and voltages, include conversion loss and reserve, then test the heater duty needed for valid sensing.
6. Record the evidence state
Record rail voltages/currents, state timing, regulator efficiency, heater warm-up requirement, battery chemistry/capacity/cutoff, temperature, radio retries, and measured cycle energy.
7. Check yourself
Why not add the 3.3 V and 5 V currents directly?
Why does 30 seconds mean 15 mA average heater current?
Does 19.5 hours predict field runtime?
The arithmetic reproduces the chapter's 92.4 mA base rail, 150 mA heater, 300 s cycle, and 7.40 Wh battery case.
- Battery
- Usable energy changes with load, temperature, ageing, cutoff voltage, and cell chemistry.
- Converters
- Regulator efficiency and quiescent current must be included per rail.
- Loads
- Boot, radio retries, sensor warm-up, heater regulation, and sleep states vary.
Correct, not complete: this ledger does not predict field battery life or qualify the heater cycle.
Eddie guides