A field team faces an unresolved physical question: What physically moves when a vibration reading rises from 0.05g to 0.5g? They must answer it before changing acceleration on the real device. Predict the direction first.
See the relationship before changing it
The figure reads from left to right. The blue card is acceleration. The middle card applies this page's relationship. The green card is si acceleration. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
The retained audit below checks several chapter fixtures. This added model holds every other chapter fixture fixed, so the numeric fixture does not switch without explanation.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline for acceleration is 0.5.
- 2
Name the relationship. 0.05g → 31.1 pm → 31.1 aF → code 410 0.5g → 311 pm → 311 aF → code 4,096 8g/65,536 = 122 ug/LSB
- 3
Substitute the chapter fixture. Set acceleration to 0.5. The page ledger gives si acceleration as 4.91 m/s^2.
- 4
Read the result. Keep m/s^2 beside the value. Use it only inside the technical boundary on this page.
Predict, then change acceleration
Try Predict the direction of si acceleration. Move one control, calculate, then check your prediction.
Observe The 0.5g alert is far above the ideal code step, but that does not eliminate mounting or noise errors. Reset the control to 0.5 and compare si acceleration.
Explain Only acceleration moves here. The other chapter fixtures remain fixed.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
1. Begin inside the sensor
A MEMS accelerometer lets a proof mass move against springs. Electronics measure a capacitance change and turn it into a code.
2. Name every algebra move
Convert ga = g reading × 9.81.
Divide by spring frequency squaredx = a/(2πfn)².
Scale the differential gapΔC ≈ C0(2x/d0).
Divide the rangeq = 8g/2¹⁶.
3. Reproduce the chapter
0.5g → 311 pm → 311 aF → code 4,096
8g/65,536 = 122 µg/LSB
Linear motion makes the ten-times acceleration change remain ten-times through displacement and capacitance.
4. Try the acceleration
TryMove from the baseline to the alert.
ObserveMotion, capacitance, and code all scale with acceleration in this small-signal model.
ExplainThe 0.5g alert is far above the ideal code step, but that does not eliminate mounting or noise errors.
The chain is quasi-static and idealized.
- Mechanics
- No damping, cross-axis response, or shock saturation
- Capacitance
- Small-displacement parallel-plate approximation
- Code
- No analogue noise, offset, drift, or calibration error
Validate the assembled sensor and mounting.
5. Keep the chain intact
Store range, bandwidth, mounting, calibration, sampling, feature code, and alert threshold with the event.
6. Test more than resolution
Inject known vibration across temperature, axes, fixtures, and frequencies before treating the code gap as certainty.
7. Check yourself
Why does mass cancel?
Why is 0.5g ten times the motion?
Does a large code gap prove a bearing fault?
The g thresholds come from the chapter; sensing-element figures are catalog-typical assumptions.
- 0.05g and 0.5g
- Chapter pipeline
- 20 kHz, 1 pF, 2 µm
- Stated teaching assumptions
- ±4g, 16 bit
- Typical output example
Correct, not complete: this chain does not diagnose a machine.
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