Three Formulas, Three Design Questions
Three Formulas, Three Design Questions
Ada re-derives this chapter’s own numbers step by step, at full precision
ADA · CALCULATION AUDIT
Three Formulas, Three Design Questions
The chapter states three headline results — a 1 ms debounce time constant, a 13.5 pF antenna capacitor, and a 130-ohm LED resistor. Each comes from a different formula: RC sets timing, LC sets frequency, and Ohm’s law sets current. This audit re-derives all three, showing three formulas that answer three design questions.
Companion to the chapter Conductors, Insulators, Semiconductors — every number here comes from that chapter.
See the relationship before changing it
The figure reads from left to right. The blue card is led resistor. The middle card applies the page rule. The green card is led current. Walk the arrows once: set the input, apply the rule, then read the result with its unit.
Derive the baseline in four named moves
- 1
Name the input. The chapter baseline is 150 ohm.
- 2
Name the relationship. current = 1.3 V / resistor x 1000
- 3
Substitute with units. 1.3 / 150 x 1000 = 8.67 mA
- 4
Read the result. Keep the unit beside the value. Use it only inside the technical boundary on this page.
Predict, then change led resistor
Try Predict the direction of current = 1.3 V / resistor x 1000. Test another led resistor, then compare led current.
Observe A larger resistor lowers current and heat, but also lowers light output. Reset led resistor to 150 and compare led current.
Explain A larger resistor lowers current and heat, but also lowers light output.
Check yourself
What should you do before trusting a moved-control result?
What does this small model leave out?
Ada: This chapter states three headline results — a 1 ms debounce time constant, a 13.5 pF antenna capacitor, and a 130-ohm LED resistor. Each comes from a different formula, so let me re-derive all three from scratch.
- RC time constant.
tau = R x C = 10,000 ohms x 0.0000001 F = 0.001 s = 1 ms. A capacitor reaches1 - e^-1 = 0.6321 = 63.2%of final voltage in one tau and1 - e^-5 = 0.99326 = 99.3%after5 tau = 5 ms, so a 1 ms filter rides comfortably over sub-10 ms switch bounce. - LC resonance. Inverting
f = 1 / (2 pi x sqrt(LC))givesLC = 1 / (2 pi x 433,000,000)^2 = 1.35103e-19. WithL = 10 nH,C = 1.35103e-19 / 10e-9 = 1.35103e-11 F = 13.51 pF. Feeding 10 nH and 13.5 pF back into the forward formula returns433.2 MHz, closing the loop. - Ohm’s law LED.
R = (3.3 V - 2.0 V) / 0.010 A = 130 ohms. Rounding up to a 150-ohm standard part drops the current to1.3 V / 150 ohms = 8.67 mAand dissipates(0.010 A)^2 x 150 ohms = 0.015 W— safe for a 1/8 W (0.125 W) resistor.
Each formula answers a different design question: RC sets timing, LC sets frequency, and Ohm’s law sets current. Notice too that snapping each result to the nearest standard component nudges the real value — 130 ohms becomes 150, 13.51 pF becomes 13.5 — which is why the calculation is where the check starts, not where it ends.
The three formula checks deliberately do not simulate component tolerances, parasitic capacitance and inductance, diode nonlinearity, source impedance, or temperature; the RC, LC, and LED examples use nominal lumped values.
Work the audit first, then check the displayed derivation.
Every number above is taken from the chapter’s own material and re-derived step by step.